== Напредни извештаи од базата (SQL и складирани процедури)

- Ресторан со најмногу нарачки во последните 3 месеци (приказ на ресторани со сите нарачки за последните 3 месеци, сортирани?)
{{{#!sql
SELECT q1.restoran_ime as restoran, q1.naracki as broj_na_naracki 
FROM(
SELECT r.restoran_ime, COUNT(n.naracka_id) as naracki
FROM restoran as r
JOIN meni as m on r.restoran_id=m.restoran_id 
JOIN obrok as o on m.meni_id=o.meni_id 
JOIN se_sostoi_od as sso on o.obrok_id=sso.obrok_id 
JOIN naracka as n on sso.naracka_id=n.naracka_id
where n.naracana_na between (now()-interval '3 months') and now()
GROUP BY r.restoran_ime) q1
WHERE q1.naracki=(SELECT MAX(naracki)FROM (
SELECT r.restoran_ime, COUNT (n.naracka_id) as naracki
FROM restoran as r
JOIN meni as m on r.restoran_id=m.restoran_id 
JOIN obrok as o on m.meni_id=o.meni_id 
JOIN se_sostoi_od as sso on o.obrok_id=sso.obrok_id 
JOIN naracka as n on sso.naracka_id=n.naracka_id
where n.naracana_na between (now()-interval '3 months') and now()
GROUP BY r.restoran_ime) q2
)
}}}
- Ресторан со најголем профит (исто како горе)
{{{#!sql
select rr.restoran_ime as restoran, q1.cena_vkupna as profit from restoran rr join(select r.restoran_id,sum(sso.cena * sso.kolicina) as cena_vkupna 
from restoran r
join meni as m on r.restoran_id=m.restoran_id 
join obrok as o on m.meni_id=o.meni_id 
join se_sostoi_od as sso on o.obrok_id=sso.obrok_id 
join naracka as n on sso.naracka_id = n.naracka_id
group by r.restoran_id)q1
on q1.restoran_id=rr.restoran_id
where cena_vkupna=(select max(cena_vkupna) from(
select r.restoran_id,sum(sso.cena * sso.kolicina) as cena_vkupna 
from restoran r
join meni as m on r.restoran_id=m.restoran_id 
join obrok as o on m.meni_id=o.meni_id 
join se_sostoi_od as sso on o.obrok_id=sso.obrok_id 
join naracka as n on sso.naracka_id = n.naracka_id
group by r.restoran_id
)q2)
}}}
- Најнарачан производ по ресторан сортиран
{{{#!sql
select q1.restoran_ime as restoran, MAX(q1.obrok_ime) as obrok, MAX(q1.br_obroci) as broj_naracki FROM(
SELECT r.restoran_ime, o.obrok_ime,  SUM(sso.kolicina) as br_obroci
FROM restoran as r
JOIN meni as m on r.restoran_id=m.restoran_id 
JOIN obrok as o on m.meni_id=o.meni_id 
JOIN se_sostoi_od as sso on o.obrok_id=sso.obrok_id 
JOIN naracka as n on sso.naracka_id=n.naracka_id
GROUP BY r.restoran_ime, o.obrok_ime)q1
group by restoran
order by broj_naracki desc
}}}
- Кој корисник колку има платено во секој ресторан подредено
{{{#!sql
select k2.user_ime as ime, k2.user_prezime as prezime, r2.restoran_ime as restoran, q1.plateno as plateno from( 
select ku.user_id, r.restoran_id, sum(sso.cena * sso.kolicina) as plateno
from korisnik k
join kupuvac as ku on k.user_id =ku.user_id 
join naracka as n on ku.user_id =n.user_id_kupuvac 
join se_sostoi_od as sso on n.naracka_id =sso.naracka_id 
join obrok as o on sso.obrok_id =o.obrok_id 
join meni as m on o.meni_id=m.meni_id 
join restoran as r on m.restoran_id =r.restoran_id 
group by  ku.user_id ,r.restoran_id)q1 join korisnik k2 on q1.user_id=k2.user_id  join restoran r2 on q1.restoran_id=r2.restoran_id
order by plateno desc
}}}