source: node_modules/ramda/es/groupWith.js

import _curry2 from "./internal/_curry2.js";
/**
 * Takes a list and returns a list of lists where each sublist's elements are
 * all satisfied pairwise comparison according to the provided function.
 * Only adjacent elements are passed to the comparison function.
 *
 * @func
 * @memberOf R
 * @since v0.21.0
 * @category List
 * @sig ((a, a) → Boolean) → [a] → [[a]]
 * @param {Function} fn Function for determining whether two given (adjacent)
 *        elements should be in the same group
 * @param {Array} list The array to group. Also accepts a string, which will be
 *        treated as a list of characters.
 * @return {List} A list that contains sublists of elements,
 *         whose concatenations are equal to the original list.
 * @example
 *
 * R.groupWith(R.equals, [0, 1, 1, 2, 3, 5, 8, 13, 21])
 * //=> [[0], [1, 1], [2], [3], [5], [8], [13], [21]]
 *
 * R.groupWith((a, b) => a + 1 === b, [0, 1, 1, 2, 3, 5, 8, 13, 21])
 * //=> [[0, 1], [1, 2, 3], [5], [8], [13], [21]]
 *
 * R.groupWith((a, b) => a % 2 === b % 2, [0, 1, 1, 2, 3, 5, 8, 13, 21])
 * //=> [[0], [1, 1], [2], [3, 5], [8], [13, 21]]
 *
 * const isVowel = R.test(/^[aeiou]$/i);
 * R.groupWith(R.eqBy(isVowel), 'aestiou')
 * //=> ['ae', 'st', 'iou']
 */

var groupWith =
/*#__PURE__*/
_curry2(function (fn, list) {
  var res = [];
  var idx = 0;
  var len = list.length;

  while (idx < len) {
    var nextidx = idx + 1;

    while (nextidx < len && fn(list[nextidx - 1], list[nextidx])) {
      nextidx += 1;
    }

    res.push(list.slice(idx, nextidx));
    idx = nextidx;
  }

  return res;
});

export default groupWith;