= Верзија 3

== Определување функциски зависности и да нема нешто со исто име на атрибут
*s_id = statement_id
R={
pe_id, first_name, last_name, gender, address, picture, contact, embg, date_of_birth,country, nationality, o_badge_no, o_password, o_date_of_employment, p_id, p_address, s_id, city, p_date_of_employment, badge_no, rank, p_password, statement_id, statement_date, description, incident_timestamp, incident_place, e_id, e_name, e_type, is_found, e_picture, c_id, c_name, opening_date, c_status, date_of_closing, sc_description, final_document, t_id, t_name
}

pe_id -> first_name, last_name, gender, address, picture, contact, embg, date_of_birth, country, nationality
o_badge_no -> s_id, pe_id, o_password, o_date_of_employment 
p_id -> p_address, o_badge_no, s_id
s_id -> city
badge_no -> pe_id, p_date_of_employment, rank, p_password
statement_id -> c_id, statement_date, description, incident_timestamp, incident_place, badge_no
e_id -> e_name, e_type, is_found, e_picture
c_id -> c_name, opening_date, c_status, e_id, p_id, date_of_closing
final_document->  sc_description, date_of_closing
t_id -> t_name


### Лево

- statement_id
- final_document
- t_id

### Десно

- first_name
- last_name
- gender
- address
- picture
- contact
- embg
- date_of_birth
- country
- nationality
- o_password
- o_date_of_employment
- p_address
- city
- p_date_of_employment
- rank
- p_password
- statement_date
- description
- incident_timestamp
- incident_place
- e_name
- e_type
- is_found
- e_picture
- c_name
- opening_date
- c_status
- sc_description
- t_name
- date_of_closing

### Двете

- pe_id
- o_badge_no
- p_id
- s_id
- badge_no
- e_id
- c_id


statement_id+={statement_id ,c_id, statement_date, description, incident_timestamp, incident_place, badge_no,c_name, opening_date, c_status, e_id, p_id, date_of_closing, pe_id, p_date_of_employment, rank, p_password, first_name, last_name, gender, address, picture, contact, embg, date_of_birth, country, nationality, p_address, o_badge_no, s_id, city, e_name, e_type, is_found, e_picture} 
 не ги содржи сите атрибути
 
final_document+={final_document, sc_description, date_of_closing} не ги содржи сите атрибути

t_id+={t_id, t_name} не ги содржи сите атрибути

statement_id, final_document+={statement_id, final_document, c_id, statement_date, description, incident_timestamp, incident_place, badge_no, sc_description, date_of_closing, c_name, opening_date, c_status, e_id, p_id, pe_id, p_date_of_employment, rank, p_password, first_name, last_name, gender, address, picture, contact, embg, date_of_birth, country, nationality, p_address, o_badge_no, s_id, city e_name, e_type, is_found, e_picture} не ги содржи сите атрибути

statement_id, t_id+={statement_id, t_id, c_id, statement_date, description, incident_timestamp, incident_place, badge_no, t_name, c_name, opening_date, c_status, e_id, p_id, date_of_closing, e_name, e_type, is_found, e_picture, p_address, o_badge_no, s_id, city, pe_id, p_date_of_employment, rank, p_password, first_name, last_name, gender, address, picture, contact,  embg, date_of_birth, country, nationality, o_password, o_date_of_employment} не ги содржи сите атрибути

final_document, t_id+={final_document, t_id, sc_description, date_of_closing, t_name} не ги содржи сите атрибути

**final_document, t_id, statement_id+**={final_document, t_id, statement_id, sc_description, date_of_closing,  t_name, c_id, statement_date, description, incident_timestamp, incident_place, badge_no, c_name, opening_date, c_status, e_id, p_id, pe_id, p_date_of_employment, rank, p_password, e_name, e_type, is_found, e_picture,  p_address, o_badge_no, s_id, o_password, o_date_of_employment, city, first_name, last_name, gender, address, picture, contact, embg, date_of_birth, country, nationality}
**Следува дека е единствен кандидат клуч и го прогласуваме за примарен клуч.** 
```

в) Во ваква дефинирана релација нема повеќекратни зависности, па со тоа следува дека задоволува **1НФ**.

Парцијална зависност постои, и со тоа заклучуваме дека не е задоволена **2НФ**.

Декомпозиција:

**R1{s_id, city}** **е во BCNF**

R2{c_id, final_document, t_id, statement_id, sc_description, date_of_closing,  t_name, c_id, statement_date, description, incident_timestamp, incident_place, badge_no, c_name, opening_date, c_status, e_id, p_id,
pe_id, p_date_of_employment, rank, p_password, e_name, e_type, is_found, e_picture,  p_address, o_badge_no, s_id, o_password, o_date_of_employment, first_name, last_name, gender, address, picture, contact, embg, date_of_birth, country, nationality} 

---

R2 не е во 3НФ поради e_id -> e_name, e_type, is_found, e_picture

**R21{e_id, e_name, e_type, is_found, e_picture} е во BCNF**

R22{ final_document, t_id, statement_id, sc_description, date_of_closing,  t_name, c_id, statement_date, description, incident_timestamp, incident_place, badge_no, c_name, opening_date, c_status, e_id, p_id, pe_id, p_date_of_employment, rank, p_password, p_address, o_badge_no, s_id, o_password, o_date_of_employment, first_name, last_name, gender, address, picture, contact, embg, date_of_birth, country, nationality}

---

R22 не е во 3НФ поради pe_id ****-> first_name, last_name, gender, address, picture, contact, embg, date_of_birth, country, nationality

**R221{pe_id, first_name, last_name, gender, address, picture, contact, embg, date_of_birth, country, nationality}е во BCNF**

R222{ final_document, t_id, statement_id, sc_description, date_of_closing,  t_name, c_id, statement_date, description, incident_timestamp, incident_place, badge_no, c_name, opening_date, c_status, e_id, p_id, pe_id, p_date_of_employment, rank, p_password, p_address, o_badge_no, s_id, o_password, o_date_of_employment

---

R222 не е во 3НФ поради bange_no → pe_id, p_date_of_employment, rank, p_password

**R2221{badge_no, pe_id, p_date_of_employment, rank, p_password} е во BCNF**
R2222{final_document, t_id, statement_id, sc_description, date_of_closing,  t_name, c_id, statement_date, description, incident_timestamp, incident_place, badge_no, c_name, opening_date, c_status, e_id, p_id, p_address, o_badge_no, s_id, o_password, o_date_of_employment}

---

R2222 не е во 3НФ поради o_badge_no -> s_id, pe_id, o_password, o_date_of_employment 

**R22221{o_badge_no, s_id, pe_id, o_password, o_date_of_employment} е во BCNF**
R22222{final_document, t_id, statement_id, sc_description, date_of_closing,  t_name, c_id, statement_date, description, incident_timestamp, incident_place, badge_no, c_name, opening_date, c_status, e_id, p_id, p_address, o_badge_no}

---

R22222 не е во 3НФ поради p_id -> p_address, o_badge_no, s_id

**R222221{p_id, p_address, o_badge_no, s_id}е во BCNF**
R222222{final_document, t_id, statement_id, sc_description, date_of_closing,  t_name, c_id, statement_date, description, incident_timestamp, incident_place, badge_no, c_name, opening_date, c_status, e_id, p_id}

---

R222222 не е во 3НФ поради c _id -> c_name, opening_date, c_status, e_id, p_id, date_of_closing

**R2222221{c_id, c_name, opening_date, c_status, e_id, p_id, date_of_closing}е во BCNF**
R2222222{final_document, t_id, statement_id, sc_description,  t_name, c_id, statement_date, description, incident_timestamp, incident_place, badge_no}

---

R2222222 не е во 3НФ поради **t_id** -> t_name

R222222221**{t_id, t_name} е во BCNF**
R222222222{final_document, t_id, statement_id, sc_description, c_id, statement_date, description, incident_timestamp, incident_place, badge_no}

---

R222222222 не е во 3НФ поради final_document->  sc_description, date_of_closing

**R222222221{final_document, sc_description, date_of_closing}е во BCNF**
R222222222{final_document, t_id, statement_id, c_id, statement_date, description, incident_timestamp, incident_place, badge_no}

---

R222222222 не е во 3НФ поради **statement_id** -> c_id, statement_date, description, incident_timestamp, incident_place, badge_no

**R2222222221{statement_id , c_id, statement_date, description, incident_timestamp, incident_place, badge_no}е во BCNF**

**R2222222222{final_document, t_id, statement_id} е во BCNF**

== Релации

**Sector_of_interal_affairs{s_id, city}** **е во BCNF**

**Evidence{e_id, e_name, e_type, is_found, e_picture} е во BCNF**

**People{pe_id, first_name, last_name, gender, address, picture, contact, embg, date_of_birth, country, nationality}е во BCNF**

**Policeman{badge_no, pe_id, p_date_of_employment, rank, p_password} е во BCNF**

**Officer{o_badge_no, s_id, pe_id, o_password, o_date_of_employment} е во BCNF**

**Police_station{p_id, p_address, o_badge_no, s_id}е во BCNF**

**Crime_case{c_id, c_name, opening_date, c_status, e_id, p_id, date_of_closing}е во BCNF**

**Type_of_crime{t_id, t_name} е во BCNF**

**Solved_case{final_document, sc_description, date_of_closing}е во BCNF**

**Statement{statement_id , c_id, statement_date, description, incident_timestamp, incident_place, badge_no}е во BCNF**

**Statement_and_case{final_document, t_id, statement_id} е во BCNF**


*резултатот е различен од оригиналниот модел.

Дискусија на разликите: 

Табелите каде што се чуваат acused, witness и victims се испуштаат. За да се реши ова би можело да има индиректна врска преку Statements со атрибут statement_of каде што можеме да имаме три вредности соодветно acused, witness и victims.

Редундантно повторување на слични атрибути, тоа се забележува кај Officer и Policeman. Едно решение за ова би било табела вработени каде што би се чувал атрибут is_officer. Со тоа би се изменила целосната структура на базата и не би ги имале officer и policeman. 

Имаме исто така директна врска од Crime_case за Evidence, каде што во првичниот модел се индиректно поврзани преку Mentions_evidence и Statements.