Version 6 (modified by 8 days ago) ( diff ) | ,
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Аналитика и статистика ¶
Детален преглед на трансакции помеѓу корисниците по датум ¶
SELECT tm.s_account_id AS sender_id, a_s.username AS sender_username, tm.r_account_id AS receiver_id, a_r.username AS receiver_username, tm.t_id, t.timestamp, t.amount FROM transferred_money tm JOIN account a_s ON tm.s_account_id = a_s.id JOIN account a_r ON tm.r_account_id = a_r.id JOIN "transaction" t ON tm.t_id = t.id;
Трансакции до одреден датум и време ¶
SELECT tm.s_account_id AS sender_id, a_s.username AS sender_username, tm.r_account_id AS receiver_id, a_r.username AS receiver_username, tm.t_id, t.timestamp, t.amount FROM transferred_money tm JOIN account a_s ON tm.s_account_id = a_s.id JOIN account a_r ON tm.r_account_id = a_r.id JOIN "transaction" t ON tm.t_id = t.id WHERE timestamp<'2025-03-23 20:30:00.000000';
Трансакции по валута, подредени по време ¶
SELECT tm.s_account_id AS sender_id, a_s.username AS sender_username, tm.r_account_id AS receiver_id, a_r.username AS receiver_username, tm.t_id, t.timestamp, t.amount, tm.currency FROM transferred_money tm JOIN account a_s ON tm.s_account_id = a_s.id JOIN account a_r ON tm.r_account_id = a_r.id JOIN "transaction" t ON tm.t_id = t.id WHERE currency='EUR' ORDER BY timestamp;
Максимум, минимум и просечен износ на сума по трансакција во одредена валута ¶
SELECT max(t.amount) as maximum, avg(t.amount) as "average", min(t.amount) as minimum FROM transferred_money tm JOIN account a_s ON tm.s_account_id = a_s.id JOIN account a_r ON tm.r_account_id = a_r.id JOIN "transaction" t ON tm.t_id = t.id WHERE currency='USD';
Прикажи ги корисниците со најголем број на трансфери на пари(број на с-ка, корисничко име, e-mail, број на трансфери и ранг во растечки редослед) ¶
WITH transfer_frequency AS ( SELECT t.s_id AS account_id, COUNT(*) AS transfer_count FROM transfer t GROUP BY t.s_id UNION ALL SELECT t.r_id AS account_id, COUNT(*) AS transfer_count FROM transfer t GROUP BY t.r_id ) SELECT * FROM ( SELECT a.id AS account_id, a.username, a.email, tf.transfer_count, RANK() OVER (ORDER BY tf.transfer_count DESC) AS transfer_rank FROM account a JOIN transfer_frequency tf ON a.id = tf.account_id ) ranked_accounts WHERE transfer_rank <= 3 ORDER BY transfer_rank;
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