| Version 5 (modified by , 9 months ago) ( diff ) |
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Напредни извештаи од базата (SQL и складирани процедури)
Извештај за број на откжани, успешни резервации по ресторан
SELECT
au.first_name,
au.last_name,
au.membership_level,
au."role",
rh.restaurant_id,
COUNT(CASE WHEN rh.cancellation_reason = 'Canceled by user' THEN 1 END) AS canceled_by_user_per_restaurant,
COUNT(CASE WHEN rh.cancellation_reason = '/' THEN 1 END) AS succesfull_by_user_per_restaurant,
COUNT(CASE WHEN rh.cancellation_reason = 'Canceled by restaurant' THEN 1 END) AS canceled_by_restaurant,
COUNT(rh.cancellation_reason) AS total_cancellations_per_restaurant
FROM reservation_history rh
INNER JOIN app_user au ON rh.customer_id = au.id
WHERE rh.cancellation_reason IS NOT NULL
GROUP BY au.first_name,
au.last_name,
au.membership_level,
au."role",
rh.restaurant_id
ORDER BY canceled_by_user_per_restaurant DESC;}}}
== Извештај за најмногу резервации по ресторан
{{{
SELECT r.restaurantId, r."name", COUNT(res.reservationId) AS totalReservations
FROM restaurants r
JOIN reservations res ON r.restaurantId = res.restaurantId
GROUP BY r.restaurantId, r."name"
ORDER BY totalReservations desc
}}}
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