| Version 2 (modified by , 9 months ago) ( diff ) |
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Напредни извештаи од базата (SQL и складирани процедури)
Извештај за секој салон со бројот на вработени, термини,резервации
SELECT DISTINCT
fc.id AS fitnes_centar_id,
br_instruktori.broj_instruktori,
br_termini.broj_termini,
br_rezervacii.broj_rezervacii
FROM Fitnes_Centar AS fc
LEFT JOIN (
SELECT id_gym, COUNT(user_id_instruktor) AS broj_instruktori
FROM Fitnes_Instruktor
GROUP BY id_gym
) AS br_instruktori ON fc.id = br_instruktori.id_gym
LEFT JOIN (
SELECT fi.id_gym, COUNT(t.termin_id) AS broj_termini
FROM Fitnes_Instruktor AS fi
JOIN Termin AS t ON fi.user_id_instruktor = t.instruktor_id
GROUP BY fi.id_gym
) AS br_termini ON fc.id = br_termini.id_gym
LEFT JOIN (
SELECT fi.id_gym, COUNT(r.rez_id) AS broj_rezervacii
FROM Fitnes_Instruktor AS fi
JOIN Termin AS t ON fi.user_id_instruktor = t.instruktor_id
JOIN Rezervacija AS r ON t.termin_id = r.termin_id
GROUP BY fi.id_gym
) AS br_rezervacii ON fc.id = br_rezervacii.id_gym;
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