Version 18 (modified by 3 years ago) ( diff ) | ,
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Напредни извештаи од базата (SQL и складирани процедури)
Да се најде направениот промет за секој артист во изминатата година.
select u."name" , SUM(t.stripe_price) from artists a join users u on u.id = a.user_id join offers o on o.artist_id = u.id join transactions t on t.offer_id = o.id where extract (year from t.created_at) = extract (year from now() - interval '1 year') group by u.id
Да се најдат каков тип на Артисти ангажирале Организаторите во последните 6 месеци.
select distinct at2.name from organizers o left join events e on e.organizer_id = o.user_id left join offers o2 on o2.event_id = e.id left join artists a on a.user_id = o2.artist_id join artist_types at2 on at2.id = a.artist_type_id where o2.status = 'COMPLETED' and o2.completed_at between now() - interval '6 months' and now() group by o.user_id, at2.name
Да се најде просечно време (во денови) кое било потрошено од страна на Организаторите и Артистите за да склучат договор (да платат).
select avg(extract(day from o.completed_at-o.created_at)) from offers o where completed_at notnull
Во кој дел од денот се испраќаат најмногу барања за понуди.
select concat( avg(extract (hour from o.created_at))::int, ':', avg(extract (minute from o.created_at)):: int) as avgTime from offers o
Процент на успешно прифатени/реализирани понуди (во проценти).
select to_char((select ( (select count(*) from offers o where completed_at notnull) / (select count(*) from offers o2)::float) *100), 'fm00D00%')
Табеларен извештај за трансакции по артисти, по години и тримесечја.
with year_transactions as ( select distinct extract(year from (t.created_at)) as year from transactions t ) select us."name", yt.year, ( select count(t.id) from transactions t join offers o on o.artist_id = us.id and t.offer_id = o.id ) as total_transactions, ( select count(t.id) from transactions t join offers o on o.artist_id = us.id and t.offer_id = o.id where yt.year = extract(year from (t.created_at)) and extract(month from (t.created_at)) in (1,2,3) ) as total_num_trans_q1, ( select count(t.id) from transactions t join offers o on o.artist_id = us.id and t.offer_id = o.id where yt.year = extract(year from (t.created_at)) and extract(month from (t.created_at)) in (4,5,6) ) as total_num_trans_q2, ( select count(t.id) from transactions t join offers o on o.artist_id = us.id and t.offer_id = o.id where yt.year = extract(year from (t.created_at)) and extract(month from (t.created_at)) in (7,8,9) ) as total_num_trans_q3, ( select count(t.id) from transactions t join offers o on o.artist_id = us.id and t.offer_id = o.id where yt.year = extract(year from (t.created_at)) and extract(month from (t.created_at)) in (10,11,12) ) as total_num_trans_q4, ( select avg(o.price) from transactions t join offers o on o.artist_id = us.id and t.offer_id = o.id where yt.year = extract(year from (t.created_at)) and extract(month from (t.created_at)) in (1,2,3) ) as avg_trans_value_q1, ( select avg(o.price) from transactions t join offers o on o.artist_id = us.id and t.offer_id = o.id where yt.year = extract(year from (t.created_at)) and extract(month from (t.created_at)) in (4,5,6) ) as avg_trans_value_q2, ( select avg(o.price) from transactions t join offers o on o.artist_id = us.id and t.offer_id = o.id where yt.year = extract(year from (t.created_at)) and extract(month from (t.created_at)) in (7,8,9) ) as avg_trans_value_q3, ( select avg(o.price) from transactions t join offers o on o.artist_id = us.id and t.offer_id = o.id where yt.year = extract(year from (t.created_at)) and extract(month from (t.created_at)) in (10,11,12) ) as avg_trans_value_q4 from year_transactions yt, artists ar left join users us on us.id = ar.user_id;
Популарни артисти - рангирано според број на рецензии, тотална заработка и број на добиени понуди.
select u.full_name, u.email, a.city, a.country, a.price_per_hour, at2.name, coalesce(sum(t.stripe_price),0) as earnings, ( select count(o2.id) from offers o2 where o2.artist_id = a.user_id ) as num_offers, ( (5 * (select count(re.artist_id) from reviews re where re.rating = 5 and re.artist_id = a.user_id) + 4 * (select count(re.artist_id) from reviews re where re.rating = 4 and re.artist_id = a.user_id) + 3 * (select count(re.artist_id) from reviews re where re.rating = 3 and re.artist_id = a.user_id) + 2 * (select count(re.artist_id) from reviews re where re.rating = 2 and re.artist_id = a.user_id) + 1 * (select count(re.artist_id) from reviews re where re.rating = 1 and re.artist_id = a.user_id)) / ((select count(re.artist_id) from reviews re where re.artist_id = a.user_id)) ) as average_rating from users u join artists a on a.user_id = u.id join artist_types at2 on at2.id = a.artist_type_id left join reviews r on r.artist_id = a.user_id left join offers o on o.artist_id = a.user_id left join transactions t on t.offer_id = o.id group by a.user_id, u.id, at2.id order by average_rating desc, earnings desc, num_offers asc;
Број на барања испратени кон артисти.
select a.user_id, count(o.id) as num_of_offers_received from artists a join users u on u.id = a.user_id join offers o on o.artist_id = a.user_id join events e on e.id = o.event_id group by a.user_id
Просечен број на коментари/пораки кои се потребни за да се постигне договор.
-- Status 1 - vo dogovor -- Status 2 - dogovoreni -- Status 3 - otkazano with tempTable as (select oc.offer_id, count(oc.offer_id) as num_of_comments from offer_comments oc join offers as o on o.id = oc.offer_id and o.status = 2 group by oc.offer_id) select avg(t.num_of_comments) from tempTable as t
Најпопуларни жанрови според број на артисти кои ги пеат (во опаѓачки редослед).
select asg.genre_id, count(asg.genre_id) as popularity from artist_sings_genres asg group by asg.genre_id order by popularity desc
Најпопуларни локации за артисти (во опаѓачки редослед).
select e.country, count(e.country) as num_of_events from events e group by e.country order by num_of_events desc
Просечен број на артисти со кои менаџерите менаџираат.
with tempTable as (select m.user_id, count(a.user_id) from managers m left join artists a on a.manager_id = m.user_id group by m.user_id) select avg(count) from tempTable
Најпопуларни типови на настани (во опаѓачки редослед).
select et.name, count(*) as occurence from events e join event_types et on et.id = e.event_type_id group by et.name order by occurence desc;
Типови артисти според популарност (во опаѓачки редослед).
select a_t.id, a_t.name, count (distinct a.user_id) from artist_types a_t left join artists a on a.artist_type_id = a_t.id group by a_t.id, a_t.name order by count desc
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