Version 6 (modified by 3 years ago) ( diff ) | ,
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Напредни извештаи од базата (SQL и складирани процедури)
Да се најде направениот промет за артист во изминатата година
select SUM(t.stripe_price) from transactions t inner join offers o on o.artist_id = 6 and t.offer_id = o.id where extract (year from t.created_at) = extract (year from now() - interval '1 year');
Да се најдат каков тип на Артисти ангажирал Организаторот во последните 6 месеци.
select distinct at2.name from ( select o2.artist_id from users u join organizers o on o.user_id = u.id join events e on e.organizer_id = o.user_id join offers o2 on o2.event_id = e.id where e.organizer_id = 11 and o2.completed_at notnull and o2.status = 2 ) as artists join artists a on artists.artist_id = a.user_id join artist_types at2 on at2.id = a.artist_type_id;
Да се најде просечно време кое било потрошено од страна на Организаторите и Артистите за да склучат договор (да платат).
select avg(extract(day from o.completed_at-o.created_at)) from offers o where completed_at notnull
Во кој дел од денот се испраќаат најмногу барања за понуди.
select concat( avg(extract (hour from o.created_at))::int, ':', avg(extract (minute from o.created_at)):: int) as avgTime from offers o
Процент на успешно прифатени/реализирани понуди (во проценти).
select ((select count(*) from offers o where completed_at notnull)/(select count(*) from offers o2)::float)*100;
Популарни артисти - рангирано според број на рецензии, тотална заработка и број на добиени понуди
select u.full_name, u.email, a.city, a.country, a.price_per_hour, at2.name, coalesce(sum(t.stripe_price),0) as earnings, ( select count(o2.id) from offers o2 where o2.artist_id = a.user_id ) as num_offers, ( (5 * (select count(re.artist_id) from reviews re where re.rating = 5 and re.artist_id = a.user_id) + 4 * (select count(re.artist_id) from reviews re where re.rating = 4 and re.artist_id = a.user_id) + 3 * (select count(re.artist_id) from reviews re where re.rating = 3 and re.artist_id = a.user_id) + 2 * (select count(re.artist_id) from reviews re where re.rating = 2 and re.artist_id = a.user_id) + 1 * (select count(re.artist_id) from reviews re where re.rating = 1 and re.artist_id = a.user_id)) / ((select count(re.artist_id) from reviews re where re.artist_id = a.user_id)) ) as average_rating from users u join artists a on a.user_id = u.id join artist_types at2 on at2.id = a.artist_type_id left join reviews r on r.artist_id = a.user_id left join offers o on o.artist_id = a.user_id left join transactions t on t.offer_id = o.id group by a.user_id, u.id, at2.id order by average_rating desc, earnings desc, num_offers asc;
Број на барања испратени кон одреден артист за одреден настан.
select a.user_id, count(o.artist_id) as num_of_offers_received from artists a join users u on u.id = a.user_id join offers o on o.artist_id = a.user_id join events e on e.id = o.event_id where e.title = 'Igor''s Birthday' and u.username = 'test_artist_1' group by a.user_id
Просечен број на коментари/пораки кои се потребни за да се постигне договор.
-- Status 1 - dogovoreni -- Status 2 - vo dogovor -- Status 3 - otkazano with tempTable as (select oc.offer_id, count(oc.offer_id) as num_of_comments from offer_comments oc join offers as o on o.id = oc.offer_id and o.status = 1 group by oc.offer_id) select avg(t.num_of_comments) from tempTable as t
Најпопуларни жанрови според број на артисти кои ги пеат (по опаѓачки редослед)
select asg.genre_id, count(asg.genre_id) as popularity from artist_sings_genres asg group by asg.genre_id order by popularity desc
Најпопуларни локации за артисти (по опаѓачки редослед).
select e.country, count(e.country) as num_of_events from events e group by e.country order by num_of_events desc
Просечен број на артисти со кои менаџерите менаџираат
with tempTable as (select m.user_id, count(a.user_id) from managers m left join artists a on a.manager_id = m.user_id group by m.user_id) select avg(count) from tempTable
Најпопуларни типови на настани.
select et.name, count(*) as occurence from events e join event_types et on et.id = e.event_type_id group by et.name order by occurence desc;
Типови артисти според популарност (во опаѓачки редослед).
select a_t.id, a_t.name, count (distinct a.user_id) from artist_types a_t left join artists a on a.artist_type_id = a_t.id group by a_t.id, a_t.name order by count desc
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