Version 20 (modified by 2 years ago) ( diff ) | ,
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Напредни извештаи од базата (SQL и складирани процедури)
За секоја година, установа со најголем број одржани настани
select q4.god as godina, p.ime as predmet, q4.broj_casovi as broj_casovi from ( select * from ( select q1.godina as god, max(q1.broj_casovi) as maksimum from ( select extract (year from c.vreme_pocetok) as godina, p.id_predmet as predmet, count(c.id_cas) broj_casovi from predmeti p join casovi c on c.id_predmet = p.id_predmet group by godina,predmet ) q1 group by godina ) q2 join ( select extract (year from c.vreme_pocetok) as godina, p.id_predmet as predmet, count(c.id_cas) broj_casovi from predmeti p join casovi c on c.id_predmet = p.id_predmet group by godina,predmet ) q3 on q2.god=q3.godina and q2.maksimum=q3.broj_casovi ) q4 join predmeti p on p.id_predmet = q4.predmet order by godina desc;
Извештај за купувач според тромесечие, купени карти и придонес
select distinct u.user_name,u.user_surname, case when tabela.quarter=1 then tabela.broj_kupeni else 0 end as prv_kvartal_kupeni, case when tabela.quarter=2 then tabela.broj_kupeni else 0 end as vtor_kvartal_kupeni, case when tabela.quarter=3 then tabela.broj_kupeni else 0 end as tret_kvartal_kupeni, case when tabela.quarter=4 then tabela.broj_kupeni else 0 end as cetvrt_kvartal_kupeni, ------------------------------------------------------------------------------- case when tabela.quarter=1 then tabela.suma else 0 end as prv_kvartal_suma, case when tabela.quarter=2 then tabela.suma else 0 end as vtor_kvartal_suma, case when tabela.quarter=3 then tabela.suma else 0 end as tret_kvartal_suma, case when tabela.quarter=4 then tabela.suma else 0 end as cetvrt_kvartal_suma from reservation as r join client as c on c.user_id = r.user_id join movieprojection as mp on mp.projection_id = r.projection_id join users as u on u.user_id = c.user_id join( select distinct c2.user_id,extract(quarter from r2.reservation_date) as quarter,sum(mp.projection_price) as suma, count(r2.reservation_id) as broj_kupeni from reservation as r2 join movieprojection as mp on mp.projection_id = r2.projection_id join client as c2 on c2.user_id = r2.user_id group by 1,2 ) as tabela on c.user_id = tabela.user_id
Предложување на 10те најдобро рангирани настани на даден корисник, врз база на корисниците со кои стапил во интеракција во последните 2 месеци и корисници кои имаат оставено број на реплики поголем или еднаков од вкупниот просечен на број на реплики по сите корисници
select title from( select m.title, sum(mv.stars_rated) as total from replies r join discussions d on r.discussion_id = d.discussion_id join replies r2 on r2.discussion_id = d.discussion_id and r2.user_id != 1 join users u on u.user_id = r2.user_id and ( select count(r3.reply_id) from replies r3 group by u.user_id ) >= ( select count(*)::float / (select count(*)::float from users) from replies ) join movie_rates mv on mv.user_id = u.user_id join movies m on m.movie_id = mv.movie_id where r.user_id = 1 and r.date between current_date - interval '2 months' and current_date group by m.title order by sum(mv.stars_rated) desc limit 15 ) as tabela;
Број на трансакции реализирани од страна на купувачи кои оставиле позитивни рецензии (оценка над 3) кон артисти
select count (*) from ( with tempTable as (select o.* from organizers o join reviews as r on r.organizer_id = o.user_id and r.rating > 3 group by o.user_id) select t.* from events as e join tempTable as tt on tt.user_id = e.organizer_id join offers as o2 on o2.event_id = e.id join transactions as t on t.offer_id = o2.id ) as temp
Настан со најмногу заинтересирани купувачи во последните 100 дена
select p.ime as predmet, count(zz.id_ucenik) as broj_na_zainteresirani_ucenici from predmeti p join zainteresiran_za zz on zz.id_predmet = p.id_predmet join ucenici u on u.id_ucenik = zz.id_ucenik where zz.datum between current_date - interval '100 days' and current_date group by p.ime order by count(zz.id_ucenik) desc limit 1;
За даден настан, листа на сите артисти на настанот со број на активни настани во кои учествува артисот
select p.ime as predmet, n.ime as nastavnik, count(u.id_ucenik) as br_ucenici from predmeti p join predava_predmet pp on p.id_predmet = pp.id_predmet join nastavnici n on pp.id_nastavnik = n.id_nastavnik join predava_na pn on n.id_nastavnik = pn.id_nastavnik join ucenici u on u.id_ucenik =pn.id_ucenik where p.id_predmet = 1 group by p.ime, n.ime order by br_ucenici desc
Артист со максимален број на одржани настани
select q4."name", q4.surname, q4.max_broj_nastani from ( (select u."name", u.surname, count(e.id_event) as broj_nastani from artist a join users u on a.id_user =u.id_user join events e on a.id_user =e.id_user_artist group by u."name", u.surname) q1 join (select max(q2.broj_nastani) as max_broj_nastani from (select u."name", u.surname, count(e.id_event) as broj_nastani from artist a join users u on a.id_user =u.id_user join events e on a.id_user =e.id_user_artist group by u."name", u.surname ) q2 ) q3 on q1.broj_nastani=q3.max_broj_nastani) as q4
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