| Version 1 (modified by , 4 years ago) ( diff ) |
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Напредни извештаи од базата (SQL и складирани процедури)
Извештај за секоја продавница, бројот на производи во неа, вкупната вредност на производите, просечна цена по производ и вкупно направени нарачки во последните 3 месеци
select os.names, os.store_id,
coalesce((
select count(pis.product_in_store_id)
from online_stores as os
join product_in_store as pis on os.store_id=pis.store_id
),0) as vkupno_proizvodi,
(
select sum(p.price)
from online_stores as os
join product_in_store as pis on os.store_id=pis.store_id
join price as p on pis.product_in_store_id=p.product_in_store_id
) as vkupna_vrednost,
(
select avg(p.price)
from online_stores as os
join product_in_store as pis on os.store_id=pis.store_id
join price as p on pis.product_in_store_id=p.product_in_store_id
) as prosek_vrednost,
(
select count(sb.shopping_id)
from online_stores as os
join product_in_store as pis on os.store_id=pis.product_id
join orders as ord on pis.product_in_store_id=ord.product_in_store_id
join shopping_bag as sb on ord.shopping_id=sb.shopping_id
where sb.order_date between now() - interval '3 months' and now()
) as vkupno_naracki
from online_stores as os
group by 1, 2
Вработен кој извршил достава на најмногу нарачки
create view vkupen_broj_naracki as select se.shipping_employee_id, u.user_name, u.surname, count(s.shipping_id) as broj_naracki from shipping_employee as se join users as u on se.user_id=u.user_id join shipping as s on se.user_id=s.user_id join shopping_bag as sb on s.shopping_id=sb.shopping_id group by 1, 2, 3; select vbn.shipping_employee_id, vbn.user_name, vbn.surname, vbn.broj_naracki as najmnogu_naracki from vkupen_broj_naracki as vbn where vbn.broj_naracki = (select max(broj_naracki) from vkupen_broj_naracki);
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