| | 2 | == Прикажување на вработен (доктор) кој што има напишено најмногу извештаи за едно исто милениче. |
| | 3 | За да го тестираме овој прашалник ги додадовме следниве податоци: |
| | 4 | {{{ |
| | 5 | INSERT INTO project.reports |
| | 6 | (description, usersid, petsid) |
| | 7 | VALUES('Za isto zivotno', 8, 1); |
| | 8 | }}} |
| | 9 | {{{ |
| | 10 | WITH DoctorPetReportsCount AS ( |
| | 11 | SELECT |
| | 12 | u.id AS doctor_id, |
| | 13 | u.name AS doctor_name, |
| | 14 | r.petsID AS pet_id, |
| | 15 | COUNT(r.id) AS reports_count |
| | 16 | FROM |
| | 17 | project.reports r |
| | 18 | LEFT JOIN |
| | 19 | project.users u ON r.usersID = u.id |
| | 20 | GROUP BY |
| | 21 | u.id, u.name, r.petsID |
| | 22 | ), |
| | 23 | |
| | 24 | MaxReportsPerPet AS ( |
| | 25 | SELECT |
| | 26 | pet_id, |
| | 27 | MAX(reports_count) AS max_reports_count |
| | 28 | FROM |
| | 29 | DoctorPetReportsCount |
| | 30 | GROUP BY |
| | 31 | pet_id |
| | 32 | ), |
| | 33 | |
| | 34 | PetsWithMaxReports AS ( |
| | 35 | SELECT |
| | 36 | pet_id, |
| | 37 | max_reports_count |
| | 38 | FROM |
| | 39 | MaxReportsPerPet |
| | 40 | WHERE |
| | 41 | max_reports_count = (SELECT MAX(max_reports_count) FROM MaxReportsPerPet) |
| | 42 | ) |
| | 43 | |
| | 44 | SELECT |
| | 45 | dprc.doctor_id, |
| | 46 | dprc.doctor_name, |
| | 47 | dprc.pet_id, |
| | 48 | dprc.reports_count |
| | 49 | FROM |
| | 50 | DoctorPetReportsCount dprc |
| | 51 | JOIN |
| | 52 | PetsWithMaxReports pwmr ON dprc.pet_id = pwmr.pet_id AND dprc.reports_count = pwmr.max_reports_count |
| | 53 | JOIN |
| | 54 | project.users u ON dprc.doctor_id = u.id; |
| | 55 | |
| | 56 | }}} |
| 26 | | == Прикажување на вработен (доктор) кој што има напишено најмногу извештаи за едно исто милениче. |
| 27 | | За да го тестираме овој прашалник ги додадовме следниве податоци: |
| 28 | | {{{ |
| 29 | | INSERT INTO project.reports |
| 30 | | (description, usersid, petsid) |
| 31 | | VALUES('Za isto zivotno', 8, 1); |
| 32 | | }}} |
| 33 | | {{{ |
| 34 | | WITH DoctorPetReportsCount AS ( |
| 35 | | SELECT |
| 36 | | u.id AS doctor_id, |
| 37 | | u.name AS doctor_name, |
| 38 | | r.petsID AS pet_id, |
| 39 | | COUNT(r.id) AS reports_count |
| 40 | | FROM |
| 41 | | project.reports r |
| 42 | | LEFT JOIN |
| 43 | | project.users u ON r.usersID = u.id |
| 44 | | GROUP BY |
| 45 | | u.id, u.name, r.petsID |
| 46 | | ), |
| 47 | | |
| 48 | | MaxReportsPerPet AS ( |
| 49 | | SELECT |
| 50 | | pet_id, |
| 51 | | MAX(reports_count) AS max_reports_count |
| 52 | | FROM |
| 53 | | DoctorPetReportsCount |
| 54 | | GROUP BY |
| 55 | | pet_id |
| 56 | | ), |
| 57 | | |
| 58 | | PetsWithMaxReports AS ( |
| 59 | | SELECT |
| 60 | | pet_id, |
| 61 | | max_reports_count |
| 62 | | FROM |
| 63 | | MaxReportsPerPet |
| 64 | | WHERE |
| 65 | | max_reports_count = (SELECT MAX(max_reports_count) FROM MaxReportsPerPet) |
| 66 | | ) |
| 67 | | |
| 68 | | SELECT |
| 69 | | dprc.doctor_id, |
| 70 | | dprc.doctor_name, |
| 71 | | dprc.pet_id, |
| 72 | | dprc.reports_count |
| 73 | | FROM |
| 74 | | DoctorPetReportsCount dprc |
| 75 | | JOIN |
| 76 | | PetsWithMaxReports pwmr ON dprc.pet_id = pwmr.pet_id AND dprc.reports_count = pwmr.max_reports_count |
| 77 | | JOIN |
| 78 | | project.users u ON dprc.doctor_id = u.id; |
| 79 | | |
| 80 | | }}} |